From the top of a light house at a height 20 m above sea-level, the angle of depression of a ship is \[30{}^\circ .\]The distance of the ship from the foot of the light house is |
A) \[20\,\,m\]
B) \[30\,\,m\]
C) \[20\sqrt{3}\]
D) \[30\sqrt{3}\]
Correct Answer: C
Solution :
Let AB be the light house with top AB = 20 m |
In \[\Delta ABC,\]\[\tan 60{}^\circ =\frac{BC}{AB}\]\[\Rightarrow \]\[\sqrt{3}=\frac{BC}{20}\] |
\[\Rightarrow \] \[BC=20\sqrt{3}m\] |
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