| A 300 m long train crosses a platform in 39 s while it crosses a signal pole in 18 s. What is the length of the platform? |
A) 320 m
B) 350 m
C) 360 m
D) 400 m
Correct Answer: B
Solution :
| Speed of train \[=\frac{300}{18}=\frac{50}{3}m/s\] |
| Let the length of the platform be x m. |
| Then, \[\frac{x+300}{39}=\frac{50}{3}\] |
| \[\Rightarrow \]\[3\,(x+300)=39\times 50\] |
| \[\Rightarrow \] \[3x+900=1950\] |
| \[\Rightarrow \] \[3x=1050\]\[\Rightarrow \]\[x=350\,\,m\] |
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