| Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer. |
| I.\[{{(17)}^{2}}+114\div 18=x\] |
| II. \[{{(26)}^{2}}-18\times 21=y\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If \[x=y\] or the relationship cannot be established
Correct Answer: C
Solution :
| I. \[{{(17)}^{2}}+114\cdot 18=x\] |
| \[\Rightarrow \] \[{{17}^{2}}+\frac{114}{18}=x\] |
| \[\Rightarrow \] \[289+6.33=x\] |
| \[\Rightarrow \] \[295.33=x\] |
| II. \[{{(26)}^{2}}-18\times 21=y\] |
| \[\Rightarrow \]\[676-378=y\]\[\Rightarrow \]\[298=y\] |
| \[\therefore \] \[y>x\] |
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