| In how many ways can 5 keys be put in a ring? |
A) \[\frac{4!}{2}\]
B) \[\frac{5!}{2}\]
C) \[4!\]
D) \[5!\]
Correct Answer: A
Solution :
| Required number of ways \[=\frac{1}{2}(5-1)!=\frac{4!}{2}\] |
| [since, clockwise and anti-clockwise are same in calf of ring] |
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