| By how much does \[(\sqrt{12}+\sqrt{18})\]exceed \[(\sqrt{3}+\sqrt{2})\]? |
A) \[\sqrt{2}-4\sqrt{3}\]
B) \[\sqrt{3}+2\sqrt{2}\]
C) \[2\sqrt{3}-2\sqrt{2}\]
D) \[3\,\,(\sqrt{3}-\sqrt{2})\]
Correct Answer: B
Solution :
| \[\sqrt{12}+\sqrt{18}=2\sqrt{3}+3\sqrt{2}\] |
| Difference \[=(\sqrt{12}+\sqrt{18})-(\sqrt{3}+\sqrt{2})\] |
| \[=(2\sqrt{3}+3\sqrt{2})-(\sqrt{3}+\sqrt{2})=\sqrt{3}+2\sqrt{2}\] |
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