A train, 300 m long, passed a man, walking along the line in the same direction at the rate of 3 km/h in 33 s. The speed of the train is [SSC (CGL) 2010] |
A) \[30\,\,km/h\]
B) \[32\frac{8}{11}km/h\]
C) \[32\,\,km/h\]
D) \[35\frac{8}{11}km/h\]
Correct Answer: D
Solution :
Given, length of train \[=300\,\,m\] |
Let train's speed be \[x\,m/s.\] |
\[\text{Time}=33\,\,s\] |
Man's speed \[=3\,\,km/h=\frac{3\times 5}{18}m/s=\frac{5}{6}m/s\] |
\[\therefore \]Relative speed = Train's speed \[-\]Man's speed |
\[=x-\frac{5}{6}\] |
Then, \[x-\frac{5}{6}=\frac{300}{33}\] |
\[\Rightarrow \] \[\frac{6x-5}{6}=\frac{300}{33}=\frac{100}{11}\] |
\[\Rightarrow \] \[x=\frac{655}{66}m/s\] |
\[=\frac{655}{66}\times \frac{18}{5}=35\frac{8}{11}km/h\] |
You need to login to perform this action.
You will be redirected in
3 sec