| The base of a conical tent is 19.2 m in diameter and its height is 2.8 m. The area \[(\text{in}\,\,{{\text{m}}^{2}})\]of the canvas required to put up such a tent is nearly (take\[\pi =\frac{22}{7}\]) [SSC (CGL) 2002, 2008] |
A) 3017.10
B) 3170
C) 301.71
D) 30.17
Correct Answer: C
Solution :
| Radius of the circular base, \[r=\frac{19.2}{2}=9.6\,\,m\] \[h=2.8\,\,m\] |
| Slant height, \[l=\sqrt{{{h}^{2}}+{{b}^{2}}}=\sqrt{{{(2.8)}^{2}}+{{(9.6)}^{2}}}\] |
| \[=\sqrt{7.84+92.16}\] |
| \[=\sqrt{100}=10\,\,m\] |
| \[\therefore \]Area of the canvas = Surface area of cone |
| \[=\frac{22}{7}\times 9.6\times 10=301.71\,\,{{m}^{2}}\] |
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