| The cost of an apple is twice that of a banana and the cost of a banana is 25% less than that of a guava. If the cost of each type of fruit increases by 10%, then the percentage increase in the cost of 4 bananas, 2 apples and 3 guavas is [SSC (CGL) 2011] |
A) 10%
B) 12%
C) 16%
D) 18%
Correct Answer: A
Solution :
| Let CP of 1 guava be 71. |
| \[\therefore \]CP of 1 banana \[=1-\frac{25}{100}\times 1=\text{Rs}\text{.}\frac{3}{4}\] |
| Similarly, CP of 1 apple \[=2\times \frac{3}{4}=\text{Rs}\text{.}\frac{3}{2}\] |
| New prices, 1 guava \[=1+\frac{1}{10}=1.1\] |
| 1 banana \[=\frac{3}{4}+\frac{10}{100}\times \frac{3}{4}=\frac{33}{40}\] |
| 1 apple \[=\frac{3}{2}+\frac{1}{10}\times \frac{3}{2}=\frac{33}{20}\] |
| \[\therefore \]Original price of (4 bananas, 2 apples and 3 guavas) |
| \[=\left( 4\times \frac{3}{4}+2\times \frac{3}{2}+3\times 1 \right)\] |
| \[=(3+3+3)=9\] |
| New price \[=\left( 4\times \frac{33}{40}+2\times \frac{33}{20}+3\times 1.1 \right)\] |
| \[=(3.3+3.3+3.3)=9.9\] |
| \[\therefore \]Percentage increase \[=\frac{9.9-9}{9}\times 100\] |
| \[=\frac{0.9}{9}\times 100=10\]% |
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