| Directions: In the following questions, two equations I and II are given. You have to solve both the equation and give answer. |
| I. \[{{(625)}^{1/4}}x+\sqrt{1225}=155\] |
| II. \[\sqrt{196}y+13=279\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If \[x=y\] or the relationship cannot be established
Correct Answer: A
Solution :
| I. \[{{(625)}^{1/4}}x+\sqrt{1225}=155\] |
| \[\Rightarrow \] \[{{[{{(5)}^{4}}]}^{1/4}}x+35=155\] |
| \[\Rightarrow \] \[5x=155-35\] |
| \[5x=120\]\[\Rightarrow \]\[x=24\] |
| II. \[\sqrt{196}y+13=279\] |
| \[\Rightarrow \] \[14y=279-13\] |
| \[\Rightarrow \] \[14y=266\]\[\Rightarrow \]\[y=19\] |
| \[\therefore \] \[x>y\] |
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