| Directions: In the following questions, two equations I and II are given. You have to solve both the equation and give answer. |
| I. \[\frac{13}{\sqrt{x}}+\frac{9}{\sqrt{x}}=\sqrt{x}\] |
| II. \[{{y}^{4}}-\frac{{{(13\times 2)}^{9/2}}}{\sqrt{y}}=0\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If \[x=y\] or the relationship cannot be established
Correct Answer: C
Solution :
| I. \[\frac{13}{\sqrt{x}}+\frac{9}{\sqrt{x}}=\sqrt{x}\] |
| \[\Rightarrow \]\[22=(\sqrt{x})(\sqrt{x})\] |
| \[\Rightarrow \]\[x=22\] |
| II. \[{{y}^{4}}-\frac{{{(13\times 2)}^{9/2}}}{\sqrt{y}}=0\] |
| \[\Rightarrow \] \[{{y}^{4+\frac{1}{2}}}={{(26)}^{9/2}}\] |
| \[\Rightarrow \] \[{{y}^{9/2}}={{(26)}^{9/2}}\]\[\Rightarrow \]\[y=26\] |
| \[\therefore \]\[y>x\] |
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