| Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. [Allahabad Bank (PO) 2011] |
| I. \[\sqrt{25{{x}^{2}}}-125=0\] |
| II. \[\sqrt{361}y+95=0\] |
A) If\[x>y\]
B) If\[x\ge y\]
C) If\[x<y\]
D) If \[x\le y\]
E) If \[x=y\] or the relationship cannot be established
Correct Answer: A
Solution :
| I. \[\sqrt{25{{x}^{2}}}-125=0\] |
| \[\Rightarrow \]\[5x-125=0\]\[\Rightarrow \]\[x=25\] |
| II. \[\sqrt{361}y+95=0\] |
| \[\Rightarrow \]\[19y+95=0\]\[\Rightarrow \]\[y=-\,5\] |
| \[\therefore \] \[x>y\] |
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