In the given figure, if the diameter of each circle is 14 cm and DC = CE, the area of \[\Delta BDE\]is |
A) \[784\,\,c{{m}^{2}}\]
B) \[748\,\,c{{m}^{2}}\]
C) \[874\,\,c{{m}^{2}}\]
D) \[441\,\,c{{m}^{2}}\]
Correct Answer: A
Solution :
In \[\Delta BDE,\] |
\[DC=2\times \]Diameter of circle \[=2\times 14=28\,\,cm\] |
\[\therefore \]\[DE=DC+CE=28+28\,\,cm=56\,\,cm\] |
\[\therefore \]Area of \[\Delta BDE=\frac{1}{2}\times BC\times DE\] |
\[=\frac{1}{2}\times 28\times 56\] |
\[=14\times 56=784\,\,c{{m}^{2}}\] |
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