A) 50 m
B) \[75\sqrt{3}\,m\]
C) \[25\,\sqrt{3}\,m\]
D) 80 m
Correct Answer: B
Solution :
[b] Let h be the height of kite above the ground. |
In \[\Delta ABC,\]\[\sin 60{}^\circ =\frac{BC}{AB}\] |
\[\Rightarrow \] \[\frac{\sqrt{3}}{2}=\frac{h}{150}\] |
\[\Rightarrow \] \[h=\frac{\sqrt{3}\times 150}{2}\] |
\[\Rightarrow \] \[h=75\sqrt{3}\,m\] |
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