A) 22%
B) 21%
C) 24%
D) 25%
E) 20%
Correct Answer: C
Solution :
[c] Quantity of water in original mixture |
\[=120\times \frac{25}{100}=30L\] |
and quantity of milk in original mixture |
\[=120-30=90L\] |
Now, milkman sold 20 L of mixture, |
So, remaining mixture \[=120-20=100L\] |
\[\therefore \] Quantity of water in 100 L mixture |
\[=100\times \frac{25}{100}=25L\] |
and quantity of milk in 100 L mixture |
\[=100-25=75L\] |
Now, milkman made new mixture. |
\[\therefore \] Quantity of milk in new mixture \[75+16.2=91.2\,L\] |
and quantity of water in new mixture |
\[=25+3.8=28.8L\] |
Now, percentage of water in new mixture |
\[=\frac{28.8}{(91.2+28.8)}\times 100\]% |
\[=\frac{2880}{120}\]%\[=\frac{288}{12}\]%=24% |
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