s
A) 22%
B) 21%
C) 24%
D) 25%
E) 20%
Correct Answer: C
Solution :
| [c] Quantity of water in original mixture |
| \[=120\times \frac{25}{100}=30L\] |
| and quantity of milk in original mixture |
| \[=120-30=90L\] |
| Now, milkman sold 20 L of mixture, |
| So, remaining mixture \[=120-20=100L\] |
| \[\therefore \] Quantity of water in 100 L mixture |
| \[=100\times \frac{25}{100}=25L\] |
| and quantity of milk in 100 L mixture |
| \[=100-25=75L\] |
| Now, milkman made new mixture. |
| \[\therefore \] Quantity of milk in new mixture \[75+16.2=91.2\,L\] |
| and quantity of water in new mixture |
| \[=25+3.8=28.8L\] |
| Now, percentage of water in new mixture |
| \[=\frac{28.8}{(91.2+28.8)}\times 100\]% |
| \[=\frac{2880}{120}\]%\[=\frac{288}{12}\]%=24% |
You need to login to perform this action.
You will be redirected in
3 sec