The least number, that must be added to 1720, so as to obtain a perfect cube, is [SSC (10+2) 2010] |
A) 7
B) 8
C) 11
D) 13
Correct Answer: B
Solution :
Given number\[=1720\] |
To make it a perfect cube, first we find the nearest cube of given number |
\[{{11}^{3}}=11\times 11\times 11=1331\] |
\[{{12}^{3}}=12\times 12\times 12=1728\] |
\[\therefore \] It is clear that \[1720<{{(12)}^{3}}\] |
Required number \[=1728-1720=8\] |
\[\therefore \] 8 must be added to 1720, to make it a perfect cube. |
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