16 children are to be divided into two group A and B of 10 and 6 children, respectively. The average marks obtained by the children of group A is 75 and that of all the children is 76. Then, the average marks of the children of group B is |
A) 76
B) 77
C) 78
D) 79
Correct Answer: C
Solution :
Total marks of all children \[=16\times 76=1216\] |
Total marks of children in group \[A=10\times 75=750\] |
\[\because \]Total marks of children in group 8 |
\[=1216-750=466\] |
\[\therefore \]Average marks of children of group B |
\[=\frac{466}{6}=77.6\approx 78\] |
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