Milk and water are mixed in a vessel A in the proportion 5: 2 and in vessel B in the proportion 8: 5. In what proportion should quantities be taken from the two vessel, so as to form a mixture in which milk and water will be in the proportion of 9: 4? |
A) 7 : 2
B) 3 : 5
C) 3 : 4
D) 4 : 9
Correct Answer: A
Solution :
In vessel A, |
Quantity of milk \[=\frac{5}{7}\]of the weight of mixture. |
In vessel B, |
Quantity of milk \[=\frac{8}{13}\]of the weight of mixture. |
Average weight of milk in the mixture \[=\frac{9}{13}\] |
\[\therefore \]Required ratio \[=\frac{1}{13}:\frac{2}{91}=7:2\] |
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