A cylinderical road roller has its length two times its base radius. If the base radius is 42 cm. How much area does it level, if it rolls once? |
A) \[22176\,\,c{{m}^{2}}\]
B) \[22374\,\,c{{m}^{2}}\]
C) \[21220\,\,c{{m}^{2}}\]
D) \[25370\,\,c{{m}^{2}}\]
Correct Answer: A
Solution :
Here, r = 42 cm and length of the roller (h) \[=2r\] |
Length of the roller \[=2\times 42=84\,\,cm\] |
When the roller rolls cover an area equal to its curved surface area. |
\[\therefore \]Required area\[=2\pi rh=2\times \frac{22}{7}\times 42\times 84\] |
\[=22176\,\,c{{m}^{2}}\] |
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