In the figure given below, is parallel to MN, XY is parallel to LM and XZ is parallel to LN. Then, MY is |
A) The median of \[\Delta LMN\]
B) The angular bisector of\[\angle LMN\]
C) Perpendicular to LN
D) Perpendicular bisector of LN
Correct Answer: A
Solution :
Since, \[ZY=MN\] and \[ZX||YN,\] \[XNYZ\] is parallelogram. |
\[ZX=YN\] (i) |
Also, \[ZX||YN,\] and \[XY||ZL,\]\[XYLZ\]is a parallelogram. |
\[XZ=YL\] (ii) |
From Eqs. (i) and (ii), we get |
\[YN=YL\] |
So, \[MY\] is a median of \[\Delta \text{LMN}\text{.}\] |
You need to login to perform this action.
You will be redirected in
3 sec