In a single throw with two dice, find the probability of throwing as even number on one and a multiple of 3 on the other. |
A) \[\frac{1}{6}\]
B) \[\frac{5}{36}\]
C) \[\frac{11}{36}\]
D) \[\frac{5}{6}\]
Correct Answer: C
Solution :
Here, \[n\,\,(S)=6\times 6=36\] and E = Event of getting an even number on one and a multiple of 3 on the other |
\[=\{(2,3),\]\[(2,6),\]\[(4,3),\]\[(4,6),\]\[(6,3),\]\[(6,6),\]\[(3,2),\] \[(3,4),\]\[(3,6),\]\[(6,2);\]\[(6,4)\}\] |
\[P\,\,(E)=\frac{11}{36}\] |
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