| Find the number of ways of arranging the host and 8 guests at a circular table, so that the host always sits in a particular seat. |
A) 4!
B) 8!
C) 6!
D) 9!
Correct Answer: B
Solution :
| Total number of persons \[=9\] |
| Host can sit in a particular seat in one way. |
| Now, remaining position are defined relative to the host. |
| Hence, the remaining can sit in 8 place in\[{}^{8}{{P}_{8}}=8!\] |
| \[\therefore \]The number of required arrangement \[=8!\,\,\times 1=8!\] |
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