| In the figure given below, is parallel to MN, XY is parallel to LM and XZ is parallel to LN. Then, MY is |
 |
A) The median of \[\Delta LMN\]
B) The angular bisector of\[\angle LMN\]
C) Perpendicular to LN
D) Perpendicular bisector of LN
Correct Answer: A
Solution :
| Since, \[ZY=MN\] and \[ZX||YN,\] \[XNYZ\] is parallelogram. |
| \[ZX=YN\] (i) |
| Also, \[ZX||YN,\] and \[XY||ZL,\]\[XYLZ\]is a parallelogram. |
| \[XZ=YL\] (ii) |
| From Eqs. (i) and (ii), we get |
| \[YN=YL\] |
| So, \[MY\] is a median of \[\Delta \text{LMN}\text{.}\] |
You need to login to perform this action.
You will be redirected in
3 sec
