Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-31

  • question_answer
    16 children are to be divided into two group A and B of 10 and 6 children, respectively. The average marks obtained by the children of group A is 75 and that of all the children is 76. Then, the average marks of the children of group B is

    A) 76                                

    B) 77    

    C) 78        

    D) 79

    Correct Answer: C

    Solution :

    Total marks of all children \[=16\times 76=1216\]
    Total marks of children in group \[A=10\times 75=750\]
    \[\because \]Total marks of children in group 8
    \[=1216-750=466\]
    \[\therefore \]Average marks of children of group B
    \[=\frac{466}{6}=77.6\approx 78\]


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