Two vessels contain milk and water in the ratio 3: 2 and 7: 3. Find the ratio in which the contents of the two vessels have to be mixed to get a new mixture in which the ratio of milk and water 2: 1 [SSC (CGL) 2012] |
A) 2 : 1
B) 1 : 2
C) 4 : 1
D) 1 : 4
Correct Answer: B
Solution :
Given, ratio of milk and water in first vessel\[=3:2\] |
\[\therefore \]Part of milk in first vessel \[=\frac{3}{5}\] \[\left( by\frac{a}{a+b} \right)\] |
and ratio of milk and water in second vessel\[=7:3\] |
\[\therefore \]Part of milk in second vessel \[=\frac{7}{10}\] |
and new mixture ratio \[=2:1\] |
By alligation rule, |
\[\therefore \]Required ratio \[=\frac{1}{30}:\frac{1}{15}=1:2\] |
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