| Directions: In the following questions, two equations numbered I and II have been given. You have to solve both the equation and mark the correct answer. [IBPS (PO) Pre 2011] |
| I. \[3{{x}^{2}}+29x+56=0\] |
| II. \[2{{y}^{2}}+15y+25=0\] |
A) \[x<y\]
B) \[x>y\]
C) \[x\ge y\]
D) \[x\le y\]
E) Relationship between x and y cannot be Established
Correct Answer: A
Solution :
| I. \[3{{x}^{2}}+29x+56=0\] |
| \[\Rightarrow \]\[=3{{x}^{2}}+21x+8x+56=0\] |
| \[\Rightarrow \]\[3x\,(x+7)+8\,\,(x+7)=0\] |
| \[\Rightarrow \]\[(3x+8)(x+7)=0\] |
| \[\Rightarrow \]\[x=-7,\]\[x=-\frac{8}{3}\] |
| II. \[2{{y}^{2}}+15y+25=0\] |
| \[\Rightarrow \]\[2{{y}^{2}}+10y+5y+25=0\] |
| \[\Rightarrow \]\[2y\,\,(y+5)+5\,\,(y+5)=0\] |
| \[\Rightarrow \] \[(y+5)(2y+5)=0\] |
| \[\Rightarrow \] \[y=-\,\,5,\]\[y=-\frac{5}{2}\] |
| \[\therefore \]\[y>x\] |
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