| There are two containers of equal capacity. The ratio of milk to water in the first container is 3: 1, in the second container is 5: 2. If they are mixed up, then the ratio of milk to water in the mixture will be |
| [SSC (CGL) Mains 2014] |
A) 28 : 41
B) 41 : 28
C) 15 : 41
D) 41 : 15
Correct Answer: D
Solution :
| Part of milk in first container \[=\frac{3}{3+1}=\frac{3}{4}\] |
| Part of water in first container \[=\frac{1}{3+1}=\frac{1}{4}\] |
| Similarly, part of milk in second container\[=\frac{5}{5+2}=\frac{5}{7}\] |
| Part of water in second container \[=\frac{2}{5+2}=\frac{2}{7}\] |
| \[\therefore \]Required ratio of milk to water when these mixture are mixed together |
| \[\frac{\frac{3}{4}+\frac{5}{7}}{\frac{1}{4}+\frac{2}{7}}=\frac{\frac{21+20}{28}}{\frac{7+8}{28}}\] |
| \[=\frac{41}{28}\times \frac{28}{15}=\frac{41}{15}=41:15\] |
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