| Directions: In these questions two equations are given. You have to solve both the equations and give answer. |
| I. \[{{x}^{2}}-20x+91=0\] |
| II. \[{{y}^{2}}-32y+247=0\] |
A) If \[x<y\]
B) If \[x\le y\]
C) If \[x>y\]
D) If \[x\ge y\]
E) If relationship between x and y cannot be established
Correct Answer: B
Solution :
| I. \[{{x}^{2}}-20x+91=0\] |
| \[\Rightarrow \]\[{{x}^{2}}-13x-7x+91=0\] |
| \[\Rightarrow \]\[x\,\,(x-13)-7(x-13)=0\] |
| \[\Rightarrow \] \[(x-7)(x-13)=0\] |
| \[\therefore \] \[x=13,\]\[7\] |
| II. \[{{y}^{2}}-32y+247=0\] |
| \[\Rightarrow \]\[{{y}^{2}}-19y-13y+247=0\] |
| \[\Rightarrow \]\[y\,\,(y-19)-13\,\,(y-19)=0\] |
| \[\Rightarrow \] \[(y-13)(y-19)=0\] |
| \[\therefore \] \[y=13,\]\[19\] |
| Hence, \[x\le y\] |
You need to login to perform this action.
You will be redirected in
3 sec
