| In a simultaneous throw of a pair of dice, find the probability of getting prime numbers on both the faces. |
A) \[\frac{14}{36}\]
B) \[\frac{11}{36}\]
C) \[\frac{1}{4}\]
D) \[\frac{11}{15}\]
Correct Answer: C
Solution :
| \[n\,\,(S)=6\times 6=36\] and E = Event of getting prime numbers on both the dice |
| \[=\{(2,2)(2,3)(2,5)(3,2)(3,3)(3,5)(5,2)(5,3)(5,5)\}\] |
| \[P\,\,(E)=\frac{n\,\,(E)}{n\,\,(S)}=\frac{9}{36}=\frac{1}{4}\] |
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