| In a mixture of 60 L the ratio of acid and water is 2: 1. If the ratio of acid and water is to be 1: 2, then the amount of water (in litres) to be added to the mixture is [SSC (CGL) 2014] |
A) 55
B) 60
C) 60
D) 45
Correct Answer: B
Solution :
| Quantity of acid in the mixture\[=\frac{2}{3}\times 60=40L\] |
| Quantity of water \[=60-40=20L\] |
| Let required quantity of water \[=x\,\,L\] |
| \[\therefore \]\[\frac{40}{20+x}=\frac{1}{2}\]\[\Rightarrow \]\[80=20+x\] |
| \[\Rightarrow \] \[x=60\,\,L\] |
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