Pradeep invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total sum of their investment is Rs. 17880, then how much amount did Raghu invest? [Corporation Bank (PO) 2011] |
A) Rs. 6000
B) Rs. 8000
C) Rs. 7000
D) Rs. 5000
E) None of these
Correct Answer: A
Solution :
Let the amount Raghu invested be Rs. x. |
Then, amount invested by Mohit \[=x\times \frac{90}{100}=\frac{9x}{10}\] |
Now, amount invested by Pradeep |
\[=\frac{9x}{10}\times \frac{120}{100}=\frac{108x}{100}=\frac{27x}{25}\] |
\[\therefore \] \[x+\frac{9x}{10}+\frac{27x}{25}=\text{Rs}\text{. 17880}\] |
\[\Rightarrow \]\[\frac{100x+90x+108x}{100}=17880\] |
\[\Rightarrow \] \[298x=17880\times 100\] |
\[\Rightarrow \] \[x=\frac{17880\times 100}{298}\] |
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