Directions: In these given questions two equations are given. You have to solve both the equations and give answer. [IBPS RRB (Office Assistant) 2014] |
I. \[{{x}^{2}}+3x-28=0\] |
II. \[{{y}^{2}}-y-20=0\] |
A) If \[x\le y\]
B) If \[x>y\]
C) If \[x<y\]
D) If \[x\ge y\]
E) If \[x=y\] or relationship cannot be established
Correct Answer: C
Solution :
(c)I. \[{{x}^{2}}+3x-28=0\] |
\[\Rightarrow \]\[{{x}^{2}}+7x-4x-28=0\] \[\Rightarrow \] \[x\,\,(x+7)-4\,\,(x+7)=0\] \[\Rightarrow \] \[(x+7)(x-4)=0\] |
\[\therefore \]\[x=-\,7,\]\[4\] |
II. \[{{y}^{2}}-y-20=0\] |
\[\Rightarrow \]\[{{y}^{2}}-5y+4y-20=0\] \[\Rightarrow \] \[y\,\,(y-5)+4\,\,(y-5)=0\] \[\Rightarrow \] \[(y+4)(y-5)=0\] |
\[\therefore \]\[y=-\,\,4,\]\[5\] |
Hence, \[x<y\] |
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