| Directions: In these given questions two equations are given. You have to solve both the equations and give answer. [IBPS RRB (Office Assistant) 2014] |
| I. \[2{{x}^{2}}+18x+40=0\] |
| II. \[2{{y}^{2}}+15y+27=0\] |
A) If \[x\le y\]
B) If \[x>y\]
C) If \[x<y\]
D) If \[x\ge y\]
E) If \[x=y\] or relationship cannot be established
Correct Answer: E
Solution :
(e)| I. \[2{{x}^{2}}+18x+40=0\] |
| \[\Rightarrow \]\[2{{x}^{2}}+10x+8x+40=0\] |
| \[\Rightarrow \]\[2x\,\,(x+5)+8\,\,(x+5)=0\] |
| \[\Rightarrow \]\[(2x+8)(x+5)=0\] |
| \[\therefore \]\[x=-\,\,4,\]\[x=-\,\,5\] |
| II. \[2{{y}^{2}}+15y+27=0\] |
| \[\Rightarrow \]\[2{{y}^{2}}+9y+6y+27=0\] |
| \[\Rightarrow \]\[y\,\,(2y+9)+3\,\,(2y+9)=0\] |
| \[\Rightarrow \] \[(y+3)(2y+9)=0\] |
| \[\therefore \]\[y=-\,\,3,\]\[y=-\frac{9}{2}\] |
| Here, relationship cannot be established. |
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