A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: B
Solution :
[b] Given, \[\tan x=\sin 45{}^\circ \cdot \cos 45{}^\circ +\sin 30{}^\circ \] \[\Rightarrow \] \[\tan x=\frac{1}{\sqrt{2}}\times \frac{1}{\sqrt{2}}+\frac{1}{2}\] \[\Rightarrow \] \[\tan x=\frac{1}{2}+\frac{1}{2}\] \[\Rightarrow \] \[\tan x=1=\tan 45{}^\circ \]\[\Rightarrow \]\[x=45{}^\circ \]
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