A) \[4x+6y\]
B) \[x+y+4\]
C) \[9x+4y\]
D) \[4x-9y\]
Correct Answer: D
Solution :
[d] By hit and trial, we put \[x=5\]and \[y=1,\]so that |
\[(3x+7y)=(3\times 5+7\times 1)=22\] |
which is divisible by 11. |
\[\therefore \] \[(4x+6y)=(4\times 5+6\times 1)=26\] |
which is not divisible by 11; |
\[(x+y+4)=(5+1+4)=10\] |
which is not divisible by 11; |
\[(9x+4y)=(9\times 5+4\times 1)=49\] |
which is not divisible by 11; |
\[(4x-9y)=(4\times 5-9\times 1)=11\] |
which is divisible by 11. |
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