A) Rs. 4650
B) Rs. 5650
C) Rs. 6650
D) Rs. 7660
E) None of these
Correct Answer: D
Solution :
| [d] Amounts = Rs. (25500 + 8440.5) = Rs. 33940.5 |
| \[A=P{{\left( 1+\frac{R}{100} \right)}^{T}}\] |
| \[\therefore \] \[33940.5=25500{{\left( 1+\frac{R}{100} \right)}^{3}}\] |
| \[\Rightarrow \] \[\frac{33940.5}{25500}\,\,=\,\,{{\left( 1+\frac{R}{100} \right)}^{3}}\] |
| \[\Rightarrow \] \[\frac{339405}{255000}\,\,=\,\,{{\left( 1+\frac{R}{100} \right)}^{3}}\] |
| \[\Rightarrow \]\[\frac{1331}{1000}\,\,=\,\,{{\left( 1+\frac{R}{100} \right)}^{3}}\]\[\Rightarrow \]\[{{\left( \frac{11}{10} \right)}^{3}}={{\left( 1+\frac{R}{100} \right)}^{3}}\] |
| \[\Rightarrow \] \[1+\frac{R}{100}=\frac{11}{10}\]\[\Rightarrow \]\[\frac{R}{100}=\frac{11}{10}-1=\frac{1}{10}\] |
| \[\Rightarrow \] \[R=\,\,100\times \frac{1}{10}=10%\] |
| \[\therefore \] \[\text{SI}=\frac{\text{Principal}\times \text{Time}\times \text{Rate}}{\text{100}}\] |
| \[=\frac{25500\times 3\times 10}{100}=Rs.\,7650\] |
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