A) 2010
B) 2011
C) 2012
D) 2013
Correct Answer: B
Solution :
[b] Suppose commodity X will cost 40 paise more than Y after z yr. Then, \[(4.20+0.40z)-(6.30+0.15z)=0.40\] \[\Rightarrow \] \[0.25z=0.40+2.10\] \[\Rightarrow \] \[z=\frac{2.50}{0.25}=\frac{250}{25}=10\] \[\therefore \] X will cost 40 paise more than Y, 10 yr after 2001 i.e. in 2011.You need to login to perform this action.
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