The greatest number of six digits exactly divisible by 24, 15 and 36, is |
A) 999720
B) 999629
C) 999320
D) 999620
Correct Answer: A
Solution :
\[\therefore \]LCM of \[24,\]\[15,\]\[36\]\[=3\times 2\times 2\times 2\times 5\times 3=360\] |
Greatest number of 6 digits \[=999999\] |
When 999999 is divided by 360, we get 279 as remainder. |
\[\therefore \]Required number \[=999999-279=999720\] |
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