Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-41

The price of sugar having gone down by 10%, a consumer can buy 5 kg more sugar for Rs. 270. The difference between the original and reduced price per kg is                                                [SSC (CGL) 2013]

A) 62 paise

B) 60 paise

C) 75 paise

D) 53 paise

Correct Answer: B

Solution :

Let the original price of sugar be Rs. x.

Then, reduced price of sugar

\[=x-\frac{10x}{100}=\frac{90x}{100}=\text{Rs}\text{. }\frac{9x}{10}\]

Now, according to the question,

\[\frac{270}{9x/10}-\frac{270}{x}=5\]

\[\Rightarrow \] \[\frac{270/10}{9x}-\frac{270}{x}=5\]

\[\Rightarrow \] \[\frac{300}{x}-\frac{270}{x}=5\]\[\Rightarrow \]\[\frac{300-270}{x}=5\]

\[\therefore \] \[x=\frac{30}{5}=6\]

\[\therefore \]Original price of sugar = Rs. 6

Reduced price of sugar \[=\frac{9\times x}{10}=\frac{9\times 6}{10}=\text{Rs}\text{. 5}\text{.40}\]

\[\therefore \]Required difference \[=(6-5.40)=\text{Rs}\text{. 0}\text{.60}\] or 60 paise