| If the square root of x is the cube root of y, then the relation between x and y is [SSC (FCI) 2012] |
A) \[{{x}^{3}}={{y}^{2}}\]
B) \[{{x}^{2}}={{y}^{3}}\]
C) \[x=y\]
D) \[{{x}^{6}}={{y}^{5}}\]
Correct Answer: A
Solution :
| Given, \[\sqrt{x}=\sqrt[3]{y}\]\[\Rightarrow \]\[{{x}^{\frac{1}{2}}}={{y}^{\frac{1}{3}}}\] |
| On taking power of 6 both sides, |
| \[{{({{x}^{\frac{1}{2}}})}^{6}}={{({{y}^{\frac{1}{3}}})}^{6}}\Rightarrow {{x}^{3}}={{y}^{2}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
