| A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, the probability of getting one red, one white and one blue is |
A) \[\frac{4}{5}\]
B) \[\frac{18}{91}\]
C) \[\frac{15}{78}\]
D) \[\frac{4}{17}\]
Correct Answer: C
Solution :
| Total number of outcome \[={}^{18}{{C}_{3}}\] |
| Favourable cases \[={}^{6}{{C}_{1}}\times {}^{4}{{C}_{1}}\times {}^{8}{{C}_{1}}\] |
| Probability \[=\frac{{}^{6}{{C}_{1}}\times {}^{4}{{C}_{1}}\times {}^{8}{{C}_{1}}}{{}^{18}{{C}_{3}}}=\frac{6\times 4\times 8}{\frac{18\times 17\times 16}{3\times 2\times 1}}=\frac{4}{17}\] |
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