If the present population of a state is 27500 and after 2 yr it increases to 40931, then what is the rate of increase per year? [IBPS (PO/MT) Pre 2015] |
A) 25%
B) 10%
C) 17%
D) 13%
E) 22%
Correct Answer: E
Solution :
Given, population \[=27500\] |
Population after \[2\,\,yr=40931\] |
Then, \[40931=27500{{\left( 1+\frac{R}{100} \right)}^{2}}\] |
where, R is the rate of increase. |
\[\Rightarrow \]\[\frac{40931}{27500}={{\left( \frac{100+R}{100} \right)}^{2}}\] |
\[\Rightarrow \]\[1.22\times 100=100+R\] |
\[\Rightarrow \]\[122-100=R\] |
\[\Rightarrow \] \[R=22\]% |
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