If an equilateral \[\Delta ABC\]is inscribed in a circle with centre at O, then \[\angle BOC,\]\[\angle COA\]and \[\angle AOB\]are respectively [SSC (CGL) 2014] |
A) \[50{}^\circ ,\]\[60{}^\circ ,\]\[70{}^\circ \]
B) \[120{}^\circ ,\]\[120{}^\circ ,\]\[120{}^\circ \]
C) \[60{}^\circ ,\]\[60{}^\circ ,\]\[60{}^\circ \]
D) \[80{}^\circ ,\]\[120{}^\circ ,\]\[160{}^\circ \]
Correct Answer: B
Solution :
Since, given ABC is an equilateral triangle. |
So, angle formed by incentre is also equal. |
\[\therefore \]\[\angle BOC,\]\[\angle COA\]and \[\angle AOB\]are equal to \[120{}^\circ .\] |
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