What was the day of the week on 17th August, 2010? |
A) Sunday
B) Wednesday
C) Tuesday
D) Friday
Correct Answer: C
Solution :
Period upto 17th August, 2010 |
= (year 2009 + Period from 1.1,2010 to 17. 8.2010) |
Odd days in 1600 yr = 0 |
Odd days in 400 yr = 0 |
9 yr= (2 leap years + 7 ordinary years) |
\[=(2\times 2+7\times 1)=1\,\,\text{week}+4\,\,\text{days}\] |
= 4 odd days |
Number of days between 1.1. 2010 to 17.8.2010 |
= January + February + March + April + May + June + July + August |
\[=(31+28+31+30+31+30+31+17)\,\,\text{days}\] |
= 229 days = 32 weeks + 5 odd days |
Total number of odd days \[=(0+0+4+5)\,\,\text{days}\] |
= 9 days = 1 week + 2 odd days |
Hence, the required day is Tuesday. |
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