| A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is |
A) \[2.5\sqrt{3}\,\,cm\]
B) \[5\sqrt{3}\,\,cm\]
C) \[10\sqrt{3}\,\,cm\]
D) \[5\,\,cm\]
Correct Answer: D
Solution :
| Circum radius \[=\frac{2}{3}\times \text{Height}\] |
| \[\text{Height}=\frac{10\times 3}{2}=15\,\,\text{cm}\] |
| So, length of perpendicular drawn from centre |
| \[=15-10=5\,\,\text{cm}\] |
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