Three bells chime at interval of 48, 60 and 90 min, respectively. If all the three bells chime together at 10: 00 am. At what time will all the three chime again that day |
A) 1 : 00 pm
B) 2 : 00 pm
C) 8 : 00 pm
D) 10 : 00 pm
Correct Answer: D
Solution :
We have to find out the LCM of 48,60 and 90 |
\[\therefore \] LCM \[=2\times 3\times 2\times 2\times 2\times 5\times 3\] |
\[=720\min =\frac{720}{60}h=12\,\,h\] |
\[\therefore \]Bell chime together again at 10: 00 am + 12 h |
= 10: 00 pm |
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