| If \[\frac{x}{y}=\frac{3}{4},\] the ratio of \[(2x+3y)\]and \[(3y-2x)\]is |
A) 2 : 1
B) 3 : 2
C) 3 : 1
D) 1 : 1
Correct Answer: C
Solution :
| Given, \[\frac{x}{y}=\frac{3}{4}\] |
| \[\therefore \] \[4x=3y\] (i) |
| Now \[\frac{2x+3y}{3y-2x}\] (ii) |
| Put the value of '3y' in Eq. (ii) |
| \[\frac{2x+4x}{4x-2x}=\frac{6x}{2x}=3:1\] |
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