A water tank has three taps A, B and C. Tap A, when opened, can fill the water tank alone in 4 h. Tap B, when opened, can fill the water tank alone in 6 h and tap C, when opened, can empty the water tank alone in 3 h. |
If taps A, B and C are opened simultaneously, then how long will it take to fill the tank completely? |
A) 10 h
B) 8 h
C) 18 h
D) 12 h
E) None of these
Correct Answer: D
Solution :
Part of the tank filled in 1 h when all the taps are opened |
\[=\,\,\frac{1}{4}+\frac{1}{6}-\frac{1}{3}=\frac{3+2-4}{12}=\frac{1}{12}\] |
Hence, the tank will be filled in 12 h. |
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