The vessels A and B contains acid and water in the ratio 4: 3 and 5: 3, respectively. Then, the ratio in which these mixtures to be mixed to obtain a new mixture in vessel C containing acid and water in the ratio 3 : 2 is |
A) 5 : 8
B) 7 : 8
C) 7 : 5
D) 4 : 7
Correct Answer: B
Solution :
In Vessel A, part of acid \[=\frac{4}{7}\] |
In Vessel B, part of acid \[=\frac{5}{8}\] |
In Vessel C, part of acid \[=\frac{3}{5}\] |
By Alligation rule |
\[\therefore \]Required ratio \[=\frac{1}{40}:\frac{1}{30}=35:40=7:8\] |
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