| The angle between the hands of a clock at 3 : 40 would be |
A) \[130{}^\circ \]
B) \[150{}^\circ \]
C) \[140{}^\circ \]
D) \[125{}^\circ \]
Correct Answer: A
Solution :
| Relative speed of the minute and hour hand \[=5\frac{{{1}^{{}^\circ }}}{2}\]per min. |
| \[\therefore \] In 40 min, angle between them |
| \[=40\times 5.5=220{}^\circ \] |
| But hour hand is 90° ahead of minute hand at 3'O clock, |
| \[\therefore \] Required angle \[=220{}^\circ -90{}^\circ =130{}^\circ \] |
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